[BC] Radiators - Was: KKGM
PeterH5322@aol.com
PeterH5322
Tue Jul 19 11:33:05 CDT 2005
>>50 kW into a minimum conforming radiator get you
>>50,000 watts out.
>>
>>50 kW into a Franklin gets you 99,241 watts out.
>>
>>Who says there is no free lunch?
>
>Certain nit-pickers (who, me?) might point out that if a MW tx generates 50
>kW across the input terminal(s) of the antenna system, that is all the
>power
>that can be radiated, no matter what is the stated "efficiency" of the
>antenna. Antennas with greater FCC efficiency just concentrate more of the
>available tx power into radiation in the horizontal plane, at the expense
>of
>radiation in other elevations.
>
>I guess most here know this, but just in case...
Since most potential listeners reside in the horizontal plane ... few
broadcasters are selling spots to locations 500, 1000, 1500, 2000 or 2500
miles away, where one could reasonably attribute such spot sales to
radiation above the horizontal plane ... the equivalent of 99 kW (or 198
kW under maximum "Rio" rules) would be a free lunch in my book.
The listeners don't care if the power is 50,000 watts into a minimally
conforming radiator, 362.10 mV/m/kW at 1 km, or if it is 38,000 watts
into a 207 degree radiator, also 362.10 mV/m/kW at 1 km ... they still
receive precisely the same field, and that field is 50,000 watts EMRP.
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